C# winform 连连看游戏源代码

bsp;     把坐标值赋值给x1、x2、y1、y2给下一步进行判断                         */                        if (连通判断() == true)//判断两坐标点是否联通                         {                             return true;//如果联通返回true                         }                     }                 }             }             return false;//都不满足则返回false         }  

private bool 一折连(int x1, int y1, int x2, int y2)//联通形式为一个折弯的方法         {             if (y1 < y2)             {                 if (地图[y1 * 列 + x2] == 已消除)//右上 ↗                 {                     if (X直连(x1, x2, y1))                     {                         if (Y直连(y1, y2, x2))                         {                             z1.X = x2;                             z1.Y = y1;                             return true;          &n

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