JAVA设计使用管道流的发牌程序
JAVA2程序设计实用教程之Java的面向对象特征上机报告|上机实验实习报告|计算机上机实习报告|JAVA设计使用管道流的发牌程序
在例7.9中我们利用线程调度设计了一个发牌程序，请结合本例，设计使用管道流的发牌程序。
import java.awt.*;
import java.awt.event.*;
import java.io.*;
public class Card extends WindowAdapter
{
Frame f;
TextArea ta1,ta2,ta3,ta4;
public void display()
{
f = new Frame("Send Card");
f.setSize(400,300);
f.setLocation(200,140);
f.setBackground(Color.lightGray);
f.setLayout(new GridLayout(2,2));
f.addWindowListener(this);
ta1 = new TextArea("",5,10,3); //文本区没有滚动条
ta2 = new TextArea("",5,10,3);
ta3 = new TextArea("",5,10,3);
ta4 = new TextArea("",5,10,3);
Font font1 = new Font("Helvetica", Font.PLAIN, 20);
ta1.setFont(font1);ta2.setFont(font1);
ta3.setFont(font1);ta4.setFont(font1);
f.add(ta1);f.add(ta2);f.add(ta4);
f.add(ta3);f.setVisible(true);
}
public void windowClosing(WindowEvent e)
{
System.exit(0);
}
public static void main(String arg[])
{
Card p = new Card();
p.display();
PipedInputStream in=new PipedInputStream();
PipedOutputStream out=new PipedOutputStream();
try
{
in.connect(out);
}
catch(IOException ioe){ }
Sender3 s = new Sender3(out,52);
s.start(); //启动发牌线程
s.setPriority(1); //设置最高优先级,值为1
Receiver3 r1=new Receiver3(in,p.ta1); //创建四个取牌线程
Receiver3 r2=new Receiver3(in,p.ta2);
Receiver3 r3=new Receiver3(in,p.ta3);
Receiver3 r4=new Receiver3(in,p.ta4);
r1.start(); r2.start(); r3.start(); r4.start();
}
}
class Sender3 extends Thread //发牌线程
{
PipedOutputStream out;
int count;
public Sender3(PipedOutputStream out,int c)
{
this.out=out;
this.count = c;
}
public void run( )
{
try{
for (int i=1;i<=count;i++)
out.write(i);
}
catch(IOException e){}
}
}
class Receiver3 extends Thread //取牌线程
{
PipedInputStream in;
TextArea ta;
public Receiver3(PipedInputStream in,TextArea ta)
{
this.in=in;
this.ta = ta ;
}
synchronized public void run()
{
while(true)
{
try
{
int i=in.read();
if(i!=-1)
{
ta.append(" "+i);
wait(1000);
}
}
catch(IOException e){ }
catch(InterruptedException e)
{
System.out.println(e.getMessage());
}
}
}
}
结果：若图片无法显示请联系站长QQ3249114
实验总结：
在此次实验中，掌握了Java的面向对象特征。但在程序的细节上还存在着问题。